28x^2-252=0

Solution for 28x^2-252=0 equation:

28x^2-252=0

a = 28; b = 0; c = -252;
Δ = b2-4ac
Δ = 02-4·28·(-252)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*28}=\frac{-168}{56}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*28}=\frac{168}{56}
=3
$